Base | Representation |
---|---|
bin | 111101001011000011… |
… | …0010000111010111010 |
3 | 110120002012122102001010 |
4 | 1322112012100322322 |
5 | 4123020003242300 |
6 | 140203235534350 |
7 | 12330255100602 |
oct | 1722606207272 |
9 | 416065572033 |
10 | 131367243450 |
11 | 507924253a3 |
12 | 2156275a3b6 |
13 | c507224721 |
14 | 6502cd1c02 |
15 | 363cdd7a50 |
hex | 1e96190eba |
131367243450 has 24 divisors (see below), whose sum is σ = 325790764128. Its totient is φ = 35031264880.
The previous prime is 131367243433. The next prime is 131367243457. The reversal of 131367243450 is 54342763131.
It is a junction number, because it is equal to n+sod(n) for n = 131367243399 and 131367243408.
It is not an unprimeable number, because it can be changed into a prime (131367243457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 437890662 + ... + 437890961.
It is an arithmetic number, because the mean of its divisors is an integer number (13574615172).
Almost surely, 2131367243450 is an apocalyptic number.
131367243450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131367243450 is an abundant number, since it is smaller than the sum of its proper divisors (194423520678).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131367243450 is a wasteful number, since it uses less digits than its factorization.
131367243450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 875781638 (or 875781633 counting only the distinct ones).
The product of its (nonzero) digits is 181440, while the sum is 39.
The spelling of 131367243450 in words is "one hundred thirty-one billion, three hundred sixty-seven million, two hundred forty-three thousand, four hundred fifty".
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