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131374494473129 is a prime number
BaseRepresentation
bin11101110111110000000010…
…000100110101101110101001
3122020011021112101212001221022
4131313300002010311232221
5114204414431041120004
61143224335400422225
736446331305024045
oct3567600204655651
9566137471761838
10131374494473129
1138950679227696
1212899310477975
13583c73bcb6c0b
1424627b922b025
15102c54347a2be
hex777c02135ba9

131374494473129 has 2 divisors, whose sum is σ = 131374494473130. Its totient is φ = 131374494473128.

The previous prime is 131374494473113. The next prime is 131374494473191. The reversal of 131374494473129 is 921374494473131.

It is an a-pointer prime, because the next prime (131374494473191) can be obtained adding 131374494473129 to its sum of digits (62).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86130037513129 + 45244456960000 = 9280627^2 + 6726400^2 .

It is a cyclic number.

It is not a de Polignac number, because 131374494473129 - 24 = 131374494473113 is a prime.

It is not a weakly prime, because it can be changed into another prime (131374494473329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65687247236564 + 65687247236565.

It is an arithmetic number, because the mean of its divisors is an integer number (65687247236565).

Almost surely, 2131374494473129 is an apocalyptic number.

It is an amenable number.

131374494473129 is a deficient number, since it is larger than the sum of its proper divisors (1).

131374494473129 is an equidigital number, since it uses as much as digits as its factorization.

131374494473129 is an evil number, because the sum of its binary digits is even.

The product of its digits is 54867456, while the sum is 62.

The spelling of 131374494473129 in words is "one hundred thirty-one trillion, three hundred seventy-four billion, four hundred ninety-four million, four hundred seventy-three thousand, one hundred twenty-nine".