Search a number
-
+
131374494473130 = 232523796071323503
BaseRepresentation
bin11101110111110000000010…
…000100110101101110101010
3122020011021112101212001221100
4131313300002010311232222
5114204414431041120010
61143224335400422230
736446331305024046
oct3567600204655652
9566137471761840
10131374494473130
1138950679227697
1212899310477976
13583c73bcb6c0c
1424627b922b026
15102c54347a2c0
hex777c02135baa

131374494473130 has 192 divisors, whose sum is σ = 361531317288960. Its totient is φ = 33031306459008.

The previous prime is 131374494473129. The next prime is 131374494473191. The reversal of 131374494473130 is 31374494473131.

131374494473130 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 74 + 4 + 94 + 473 + 13 + 0 = 666.

131374494473130 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 98600959 + ... + 99924461.

It is an arithmetic number, because the mean of its divisors is an integer number (1882975610880).

Almost surely, 2131374494473130 is an apocalyptic number.

131374494473130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 131374494473130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (180765658644480).

131374494473130 is an abundant number, since it is smaller than the sum of its proper divisors (230156822815830).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131374494473130 is a wasteful number, since it uses less digits than its factorization.

131374494473130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1324225 (or 1324222 counting only the distinct ones).

The product of its (nonzero) digits is 9144576, while the sum is 54.

Subtracting from 131374494473130 its reverse (31374494473131), we obtain a palindrome (99999999999999).

The spelling of 131374494473130 in words is "one hundred thirty-one trillion, three hundred seventy-four billion, four hundred ninety-four million, four hundred seventy-three thousand, one hundred thirty".