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13138013893 is a prime number
BaseRepresentation
bin11000011110001011…
…00010111011000101
31020220121111020221011
430033011202323011
5203401312421033
610011401122221
7643400163334
oct141705427305
936817436834
1013138013893
115632080324
122667a89371
131314b65024
148c8c13d1b
1551d614ccd
hex30f162ec5

13138013893 has 2 divisors, whose sum is σ = 13138013894. Its totient is φ = 13138013892.

The previous prime is 13138013887. The next prime is 13138013953. The reversal of 13138013893 is 39831083131.

13138013893 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12647701444 + 490312449 = 112462^2 + 22143^2 .

It is a cyclic number.

It is not a de Polignac number, because 13138013893 - 213 = 13138005701 is a prime.

It is a super-2 number, since 2×131380138932 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13138013803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6569006946 + 6569006947.

It is an arithmetic number, because the mean of its divisors is an integer number (6569006947).

Almost surely, 213138013893 is an apocalyptic number.

It is an amenable number.

13138013893 is a deficient number, since it is larger than the sum of its proper divisors (1).

13138013893 is an equidigital number, since it uses as much as digits as its factorization.

13138013893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46656, while the sum is 40.

The spelling of 13138013893 in words is "thirteen billion, one hundred thirty-eight million, thirteen thousand, eight hundred ninety-three".