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13140011 is a prime number
BaseRepresentation
bin110010001000…
…000000101011
3220201120201002
4302020000223
511330440021
61145345215
7216455033
oct62100053
926646632
1013140011
117465315
12449820b
132950b71
141a608c3
15124850b
hexc8802b

13140011 has 2 divisors, whose sum is σ = 13140012. Its totient is φ = 13140010.

The previous prime is 13140007. The next prime is 13140013. The reversal of 13140011 is 11004131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13140011 - 22 = 13140007 is a prime.

Together with 13140013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13139974 and 13140001.

It is not a weakly prime, because it can be changed into another prime (13140013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570005 + 6570006.

It is an arithmetic number, because the mean of its divisors is an integer number (6570006).

Almost surely, 213140011 is an apocalyptic number.

13140011 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140011 is an equidigital number, since it uses as much as digits as its factorization.

13140011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 13140011 is about 3624.9153093555. The cubic root of 13140011 is about 235.9745914903.

Adding to 13140011 its reverse (11004131), we get a palindrome (24144142).

The spelling of 13140011 in words is "thirteen million, one hundred forty thousand, eleven".