Base | Representation |
---|---|
bin | 1011111100110110010110… |
… | …1100100100100000010111 |
3 | 1201112011122222011102210121 |
4 | 2333031211230210200113 |
5 | 3210241220323004033 |
6 | 43540234321132411 |
7 | 2524222503562225 |
oct | 277154554444027 |
9 | 51464588142717 |
10 | 13140011141143 |
11 | 4206713803397 |
12 | 158275718a107 |
13 | 74413694b4b3 |
14 | 335da0d13b15 |
15 | 17bc0635962d |
hex | bf365b24817 |
13140011141143 has 2 divisors, whose sum is σ = 13140011141144. Its totient is φ = 13140011141142.
The previous prime is 13140011141087. The next prime is 13140011141171. The reversal of 13140011141143 is 34114111004131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13140011141143 - 225 = 13139977586711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13140071141143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570005570571 + 6570005570572.
It is an arithmetic number, because the mean of its divisors is an integer number (6570005570572).
Almost surely, 213140011141143 is an apocalyptic number.
13140011141143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140011141143 is an equidigital number, since it uses as much as digits as its factorization.
13140011141143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 13140011141143 its reverse (34114111004131), we get a palindrome (47254122145274).
The spelling of 13140011141143 in words is "thirteen trillion, one hundred forty billion, eleven million, one hundred forty-one thousand, one hundred forty-three".
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