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13140011141143 is a prime number
BaseRepresentation
bin1011111100110110010110…
…1100100100100000010111
31201112011122222011102210121
42333031211230210200113
53210241220323004033
643540234321132411
72524222503562225
oct277154554444027
951464588142717
1013140011141143
114206713803397
12158275718a107
1374413694b4b3
14335da0d13b15
1517bc0635962d
hexbf365b24817

13140011141143 has 2 divisors, whose sum is σ = 13140011141144. Its totient is φ = 13140011141142.

The previous prime is 13140011141087. The next prime is 13140011141171. The reversal of 13140011141143 is 34114111004131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13140011141143 - 225 = 13139977586711 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13140071141143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570005570571 + 6570005570572.

It is an arithmetic number, because the mean of its divisors is an integer number (6570005570572).

Almost surely, 213140011141143 is an apocalyptic number.

13140011141143 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140011141143 is an equidigital number, since it uses as much as digits as its factorization.

13140011141143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 13140011141143 its reverse (34114111004131), we get a palindrome (47254122145274).

The spelling of 13140011141143 in words is "thirteen trillion, one hundred forty billion, eleven million, one hundred forty-one thousand, one hundred forty-three".