Base | Representation |
---|---|
bin | 10011000111110000101… |
… | …100001100100111000111 |
3 | 11122121200010201211100012 |
4 | 103013300230030213013 |
5 | 133012034301034421 |
6 | 2443351131340435 |
7 | 163635136300451 |
oct | 23076054144707 |
9 | 4577603654305 |
10 | 1314003143111 |
11 | 4672a157793a |
12 | 1927b4bb171b |
13 | 96baa266b39 |
14 | 4785323d2d1 |
15 | 242a847995b |
hex | 131f0b0c9c7 |
1314003143111 has 2 divisors, whose sum is σ = 1314003143112. Its totient is φ = 1314003143110.
The previous prime is 1314003142987. The next prime is 1314003143183. The reversal of 1314003143111 is 1113413004131.
It is a strong prime.
It is an emirp because it is prime and its reverse (1113413004131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1314003143111 - 210 = 1314003142087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314003143711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657001571555 + 657001571556.
It is an arithmetic number, because the mean of its divisors is an integer number (657001571556).
Almost surely, 21314003143111 is an apocalyptic number.
1314003143111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314003143111 is an equidigital number, since it uses as much as digits as its factorization.
1314003143111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 1314003143111 its reverse (1113413004131), we get a palindrome (2427416147242).
The spelling of 1314003143111 in words is "one trillion, three hundred fourteen billion, three million, one hundred forty-three thousand, one hundred eleven".
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