1314004032020 has 24 divisors (see below), whose sum is σ = 2806178104800. Its totient is φ = 516693110432.

The previous prime is 1314004031933. The next prime is 1314004032157. The reversal of 1314004032020 is 202304004131.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 1314004031983 and 1314004032001.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 556780190 + ... + 556782549.

It is an arithmetic number, because the mean of its divisors is an integer number (116924087700).

Almost surely, 2^{1314004032020} is an apocalyptic number.

1314004032020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1314004032020 is an abundant number, since it is smaller than the sum of its proper divisors (1492174072780).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1314004032020 is a wasteful number, since it uses less digits than its factorization.

1314004032020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1113562807 (or 1113562805 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 1314004032020 its reverse (202304004131), we get a palindrome (1516308036151).

The spelling of 1314004032020 in words is "one trillion, three hundred fourteen billion, four million, thirty-two thousand, twenty".