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1314011020215 = 3517229311931747
BaseRepresentation
bin10011000111110001001…
…010001111101110110111
311122121200200120000200210
4103013301022033232313
5133012043310121330
62443352012240503
7163635263245665
oct23076112175667
94577620500623
101314011020215
114672a5a68043
121927b7770133
1396baba9434a
14478542cdc35
15242a8ed38b0
hex131f128fbb7

1314011020215 has 192 divisors, whose sum is σ = 2398634127360. Its totient is φ = 612750458880.

The previous prime is 1314011020199. The next prime is 1314011020243. The reversal of 1314011020215 is 5120201104131.

It is not a de Polignac number, because 1314011020215 - 24 = 1314011020199 is a prime.

It is a super-2 number, since 2×13140110202152 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1314011020191 and 1314011020200.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 752151972 + ... + 752153718.

It is an arithmetic number, because the mean of its divisors is an integer number (12492886080).

Almost surely, 21314011020215 is an apocalyptic number.

1314011020215 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1314011020215 is a deficient number, since it is larger than the sum of its proper divisors (1084623107145).

1314011020215 is a wasteful number, since it uses less digits than its factorization.

1314011020215 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2042 (or 2025 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 1314011020215 its reverse (5120201104131), we get a palindrome (6434212124346).

The spelling of 1314011020215 in words is "one trillion, three hundred fourteen billion, eleven million, twenty thousand, two hundred fifteen".