Base | Representation |
---|---|
bin | 11101111000001000110101… |
… | …011110100011011010011101 |
3 | 122020020211021110000010020112 |
4 | 131320020311132203122131 |
5 | 114210334001410440040 |
6 | 1143244502204455405 |
7 | 36451263261604040 |
oct | 3570106536433235 |
9 | 566224243003215 |
10 | 131401126655645 |
11 | 389609a5416590 |
12 | 128a250354a565 |
13 | 58420c47136b2 |
14 | 2463bc4284c57 |
15 | 102d0a15a7365 |
hex | 7782357a369d |
131401126655645 has 32 divisors (see below), whose sum is σ = 196602983571456. Its totient is φ = 81906871464000.
The previous prime is 131401126655621. The next prime is 131401126655653. The reversal of 131401126655645 is 546556621104131.
It is a de Polignac number, because none of the positive numbers 2k-131401126655645 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131401126655593 and 131401126655602.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5773229 + ... + 17208498.
It is an arithmetic number, because the mean of its divisors is an integer number (6143843236608).
Almost surely, 2131401126655645 is an apocalyptic number.
It is an amenable number.
131401126655645 is a deficient number, since it is larger than the sum of its proper divisors (65201856915811).
131401126655645 is a wasteful number, since it uses less digits than its factorization.
131401126655645 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22996601.
The product of its (nonzero) digits is 2592000, while the sum is 50.
Adding to 131401126655645 its reverse (546556621104131), we get a palindrome (677957747759776).
The spelling of 131401126655645 in words is "one hundred thirty-one trillion, four hundred one billion, one hundred twenty-six million, six hundred fifty-five thousand, six hundred forty-five".
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