Base | Representation |
---|---|
bin | 1011111100110110110000… |
… | …1100001110110010101111 |
3 | 1201112011221120012022220002 |
4 | 2333031230030032302233 |
5 | 3210241431221312421 |
6 | 43540253212414515 |
7 | 2524225266004430 |
oct | 277155414166257 |
9 | 51464846168802 |
10 | 13140120104111 |
11 | 420676a266930 |
12 | 158278777743b |
13 | 7441533ac820 |
14 | 335db1599487 |
15 | 17bc10bceb0b |
hex | bf36c30ecaf |
13140120104111 has 32 divisors (see below), whose sum is σ = 17643422189568. Its totient is φ = 9451036765440.
The previous prime is 13140120104057. The next prime is 13140120104131. The reversal of 13140120104111 is 11140102104131.
It is a cyclic number.
It is not a de Polignac number, because 13140120104111 - 218 = 13140119841967 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13140120104131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24607691 + ... + 25136003.
It is an arithmetic number, because the mean of its divisors is an integer number (551356943424).
Almost surely, 213140120104111 is an apocalyptic number.
13140120104111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13140120104111 is a deficient number, since it is larger than the sum of its proper divisors (4503302085457).
13140120104111 is a wasteful number, since it uses less digits than its factorization.
13140120104111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 553191.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 13140120104111 its reverse (11140102104131), we get a palindrome (24280222208242).
It can be divided in two parts, 13140120 and 104111, that added together give a palindrome (13244231).
The spelling of 13140120104111 in words is "thirteen trillion, one hundred forty billion, one hundred twenty million, one hundred four thousand, one hundred eleven".
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