131401755141 has 4 divisors (see below), whose sum is σ = 175202340192. Its totient is φ = 87601170092.

The previous prime is 131401755127. The next prime is 131401755143. The reversal of 131401755141 is 141557104131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 141557104131 = 3 ⋅47185701377.

It is a cyclic number.

It is not a de Polignac number, because 131401755141 - 2⁶ = 131401755077 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131401755143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21900292521 + ... + 21900292526.

It is an arithmetic number, because the mean of its divisors is an integer number (43800585048).

Almost surely, 2^131401755141 is an apocalyptic number.

It is an amenable number.

131401755141 is a deficient number, since it is larger than the sum of its proper divisors (43800585051).

131401755141 is an equidigital number, since it uses as much as digits as its factorization.

131401755141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43800585050.

The product of its (nonzero) digits is 8400, while the sum is 33.

Adding to 131401755141 its reverse (141557104131), we get a palindrome (272958859272).

The spelling of 131401755141 in words is "one hundred thirty-one billion, four hundred one million, seven hundred fifty-five thousand, one hundred forty-one".