Base | Representation |
---|---|
bin | 1011111100110111001101… |
… | …1001100100111100000011 |
3 | 1201112012020222202200010201 |
4 | 2333031303121210330003 |
5 | 3210242203201340303 |
6 | 43540313212510031 |
7 | 2524231264656511 |
oct | 277156331447403 |
9 | 51465228680121 |
10 | 13140241043203 |
11 | 420682155a19a |
12 | 158280017b317 |
13 | 744172475011 |
14 | 335dc367b4b1 |
15 | 17bc1b61d81d |
hex | bf373664f03 |
13140241043203 has 2 divisors, whose sum is σ = 13140241043204. Its totient is φ = 13140241043202.
The previous prime is 13140241043183. The next prime is 13140241043231. The reversal of 13140241043203 is 30234014204131.
It is a happy number.
It is an a-pointer prime, because the next prime (13140241043231) can be obtained adding 13140241043203 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13140241043203 - 213 = 13140241035011 is a prime.
It is not a weakly prime, because it can be changed into another prime (13140241043003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570120521601 + 6570120521602.
It is an arithmetic number, because the mean of its divisors is an integer number (6570120521602).
Almost surely, 213140241043203 is an apocalyptic number.
13140241043203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140241043203 is an equidigital number, since it uses as much as digits as its factorization.
13140241043203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 13140241043203 its reverse (30234014204131), we get a palindrome (43374255247334).
The spelling of 13140241043203 in words is "thirteen trillion, one hundred forty billion, two hundred forty-one million, forty-three thousand, two hundred three".
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