131403032241041 has 4 divisors (see below), whose sum is σ = 143348762444784. Its totient is φ = 119457302037300.

The previous prime is 131403032241017. The next prime is 131403032241073. The reversal of 131403032241041 is 140142230304131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131403032241041 - 2³⁴ = 131385852371857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131403032240995 and 131403032241013.

It is not an unprimeable number, because it can be changed into a prime (131403032241641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5972865101855 + ... + 5972865101876.

It is an arithmetic number, because the mean of its divisors is an integer number (35837190611196).

Almost surely, 2^{131403032241041} is an apocalyptic number.

131403032241041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

131403032241041 is a deficient number, since it is larger than the sum of its proper divisors (11945730203743).

131403032241041 is a wasteful number, since it uses less digits than its factorization.

131403032241041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11945730203742.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 131403032241041 its reverse (140142230304131), we get a palindrome (271545262545172).

The spelling of 131403032241041 in words is "one hundred thirty-one trillion, four hundred three billion, thirty-two million, two hundred forty-one thousand, forty-one".