Base | Representation |
---|---|
bin | 1011111100110111011110… |
… | …0001000101101010010111 |
3 | 1201112012102210202012012202 |
4 | 2333031313201011222113 |
5 | 3210242323342333421 |
6 | 43540324121235115 |
7 | 2524233064063025 |
oct | 277156741055227 |
9 | 51465383665182 |
10 | 13140310121111 |
11 | 4206857550478 |
12 | 158281b332a9b |
13 | 74418387cc14 |
14 | 335dcc8dd715 |
15 | 17bc2271610b |
hex | bf377845a97 |
13140310121111 has 2 divisors, whose sum is σ = 13140310121112. Its totient is φ = 13140310121110.
The previous prime is 13140310121093. The next prime is 13140310121171. The reversal of 13140310121111 is 11112101304131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13140310121111 - 26 = 13140310121047 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13140310121171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570155060555 + 6570155060556.
It is an arithmetic number, because the mean of its divisors is an integer number (6570155060556).
Almost surely, 213140310121111 is an apocalyptic number.
13140310121111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140310121111 is an equidigital number, since it uses as much as digits as its factorization.
13140310121111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 13140310121111 its reverse (11112101304131), we get a palindrome (24252411425242).
The spelling of 13140310121111 in words is "thirteen trillion, one hundred forty billion, three hundred ten million, one hundred twenty-one thousand, one hundred eleven".
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