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131403333340021 = 523251249203327
BaseRepresentation
bin11101111000001010111001…
…000000011000101101110101
3122020021000222020021022010111
4131320022321000120231311
5114210403011313340041
61143245505153423021
736451402045243141
oct3570127100305565
9566230866238114
10131403333340021
1138961927aa1186
12128a2a1a56aa71
1358423869456b2
142463d53382221
15102d180194981
hex7782b9018b75

131403333340021 has 4 divisors (see below), whose sum is σ = 131654582543872. Its totient is φ = 131152084136172.

The previous prime is 131403333340009. The next prime is 131403333340033. The reversal of 131403333340021 is 120043333304131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (131403333340009) and next prime (131403333340033).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131403333340021 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131403333340121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125624601141 + ... + 125624602186.

It is an arithmetic number, because the mean of its divisors is an integer number (32913645635968).

Almost surely, 2131403333340021 is an apocalyptic number.

It is an amenable number.

131403333340021 is a deficient number, since it is larger than the sum of its proper divisors (251249203851).

131403333340021 is an equidigital number, since it uses as much as digits as its factorization.

131403333340021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 251249203850.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 131403333340021 its reverse (120043333304131), we get a palindrome (251446666644152).

The spelling of 131403333340021 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred thirty-three million, three hundred forty thousand, twenty-one".

Divisors: 1 523 251249203327 131403333340021