Base | Representation |
---|---|
bin | 10011000111110010100… |
… | …011001111110000000111 |
3 | 11122121202022110100200001 |
4 | 103013302203033300013 |
5 | 133012120243213421 |
6 | 2443354204302131 |
7 | 163635665460046 |
oct | 23076243176007 |
9 | 4577668410601 |
10 | 1314034351111 |
11 | 467308152979 |
12 | 192803541947 |
13 | 96bb3872901 |
14 | 4785744455d |
15 | 242ab091691 |
hex | 131f28cfc07 |
1314034351111 has 2 divisors, whose sum is σ = 1314034351112. Its totient is φ = 1314034351110.
The previous prime is 1314034351103. The next prime is 1314034351163. The reversal of 1314034351111 is 1111534304131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1314034351111 - 23 = 1314034351103 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1314034351111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314034351181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657017175555 + 657017175556.
It is an arithmetic number, because the mean of its divisors is an integer number (657017175556).
Almost surely, 21314034351111 is an apocalyptic number.
1314034351111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314034351111 is an equidigital number, since it uses as much as digits as its factorization.
1314034351111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 28.
Adding to 1314034351111 its reverse (1111534304131), we get a palindrome (2425568655242).
The spelling of 1314034351111 in words is "one trillion, three hundred fourteen billion, thirty-four million, three hundred fifty-one thousand, one hundred eleven".
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