Base | Representation |
---|---|
bin | 1011111100110111100111… |
… | …1110101000101110100111 |
3 | 1201112012112200110110111021 |
4 | 2333031321332220232213 |
5 | 3210242414430440401 |
6 | 43540332154352011 |
7 | 2524234105114630 |
oct | 277157176505647 |
9 | 51465480413437 |
10 | 13140351421351 |
11 | 4206878899a00 |
12 | 158283112b607 |
13 | 74418c2b052b |
14 | 335dd41b0887 |
15 | 17bc261732a1 |
hex | bf379fa8ba7 |
13140351421351 has 24 divisors (see below), whose sum is σ = 17375671322240. Its totient is φ = 9700327763280.
The previous prime is 13140351421283. The next prime is 13140351421361. The reversal of 13140351421351 is 15312415304131.
It is not a de Polignac number, because 13140351421351 - 211 = 13140351419303 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13140351421361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 408246861 + ... + 408279046.
Almost surely, 213140351421351 is an apocalyptic number.
13140351421351 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13140351421351 is a deficient number, since it is larger than the sum of its proper divisors (4235319900889).
13140351421351 is a wasteful number, since it uses less digits than its factorization.
13140351421351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 816525955 (or 816525944 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 13140351421351 its reverse (15312415304131), we get a palindrome (28452766725482).
The spelling of 13140351421351 in words is "thirteen trillion, one hundred forty billion, three hundred fifty-one million, four hundred twenty-one thousand, three hundred fifty-one".
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