13140353504545 has 4 divisors (see below), whose sum is σ = 15768424205460. Its totient is φ = 10512282803632.

The previous prime is 13140353504543. The next prime is 13140353504659. The reversal of 13140353504545 is 54540535304131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5724491693281 + 7415861811264 = 2392591^2 + 2723208^2 .

It is a cyclic number.

It is not a de Polignac number, because 13140353504545 - 2¹ = 13140353504543 is a prime.

It is a super-3 number, since 3×13140353504545³ (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (13140353504543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1314035350450 + ... + 1314035350459.

It is an arithmetic number, because the mean of its divisors is an integer number (3942106051365).

Almost surely, 2^{13140353504545} is an apocalyptic number.

It is an amenable number.

13140353504545 is a deficient number, since it is larger than the sum of its proper divisors (2628070700915).

13140353504545 is an equidigital number, since it uses as much as digits as its factorization.

13140353504545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2628070700914.

The product of its (nonzero) digits is 1080000, while the sum is 43.

Adding to 13140353504545 its reverse (54540535304131), we get a palindrome (67680888808676).

The spelling of 13140353504545 in words is "thirteen trillion, one hundred forty billion, three hundred fifty-three million, five hundred four thousand, five hundred forty-five".