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131404040303 = 402132679443
BaseRepresentation
bin111101001100001001…
…0101000100001101111
3110120011202212212211112
41322120102220201233
54123103413242203
6140211032342235
712331212625214
oct1723022504157
9416152785745
10131404040303
1150801178418
1221572b4497b
13c511a39303
146507b4db0b
1536412556d8
hex1e984a886f

131404040303 has 4 divisors (see below), whose sum is σ = 131436723768. Its totient is φ = 131371356840.

The previous prime is 131404040291. The next prime is 131404040333. The reversal of 131404040303 is 303040404131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131404040303 - 212 = 131404036207 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131404040333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16335701 + ... + 16343742.

It is an arithmetic number, because the mean of its divisors is an integer number (32859180942).

Almost surely, 2131404040303 is an apocalyptic number.

131404040303 is a deficient number, since it is larger than the sum of its proper divisors (32683465).

131404040303 is an equidigital number, since it uses as much as digits as its factorization.

131404040303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32683464.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 131404040303 its reverse (303040404131), we get a palindrome (434444444434).

The spelling of 131404040303 in words is "one hundred thirty-one billion, four hundred four million, forty thousand, three hundred three".

Divisors: 1 4021 32679443 131404040303