Search a number
-
+
131404313433319 is a prime number
BaseRepresentation
bin11101111000001011110011…
…011011001001010011100111
3122020021010111112111012101021
4131320023303123021103213
5114210412013214331234
61143250150324312011
736451435246014043
oct3570136333112347
9566233445435337
10131404313433319
1138962290258843
12128a3052842607
1358424b1a02a64
1424640075cb023
15102d1db2429b4
hex7782f36c94e7

131404313433319 has 2 divisors, whose sum is σ = 131404313433320. Its totient is φ = 131404313433318.

The previous prime is 131404313433317. The next prime is 131404313433359. The reversal of 131404313433319 is 913334313404131.

It is a weak prime.

It is an emirp because it is prime and its reverse (913334313404131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131404313433319 - 21 = 131404313433317 is a prime.

It is a super-2 number, since 2×1314043134333192 (a number of 29 digits) contains 22 as substring.

Together with 131404313433317, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131404313433317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65702156716659 + 65702156716660.

It is an arithmetic number, because the mean of its divisors is an integer number (65702156716660).

Almost surely, 2131404313433319 is an apocalyptic number.

131404313433319 is a deficient number, since it is larger than the sum of its proper divisors (1).

131404313433319 is an equidigital number, since it uses as much as digits as its factorization.

131404313433319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 419904, while the sum is 43.

The spelling of 131404313433319 in words is "one hundred thirty-one trillion, four hundred four billion, three hundred thirteen million, four hundred thirty-three thousand, three hundred nineteen".