1314101011 has 2 divisors, whose sum is σ = 1314101012. Its totient is φ = 1314101010.

The previous prime is 1314100987. The next prime is 1314101017. The reversal of 1314101011 is 1101014131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1314101011 - 2¹⁷ = 1313969939 is a prime.

It is a super-2 number, since 2×1314101011² = 3453722934222444242, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1314100982 and 1314101000.

It is not a weakly prime, because it can be changed into another prime (1314101017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657050505 + 657050506.

It is an arithmetic number, because the mean of its divisors is an integer number (657050506).

Almost surely, 2^1314101011 is an apocalyptic number.

1314101011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314101011 is an equidigital number, since it uses as much as digits as its factorization.

1314101011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

The square root of 1314101011 is about 36250.5311823151. The cubic root of 1314101011 is about 1095.3247887349.

Adding to 1314101011 its reverse (1101014131), we get a palindrome (2415115142).

The spelling of 1314101011 in words is "one billion, three hundred fourteen million, one hundred one thousand, eleven".