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13141040501251 = 131010849269327
BaseRepresentation
bin1011111100111010001100…
…0011010001001000000011
31201112021022201002100102001
42333032203003101020003
53210300322332020001
643540524412004431
72524260143155135
oct277164303211003
951467281070361
1013141040501251
1142070a185a923
1215829a3a60717
1374426bc98310
1433605b905055
1517bc668da001
hexbf3a30d1203

13141040501251 has 4 divisors (see below), whose sum is σ = 14151889770592. Its totient is φ = 12130191231912.

The previous prime is 13141040501249. The next prime is 13141040501263. The reversal of 13141040501251 is 15210504014131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13141040501251 - 21 = 13141040501249 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13141040501231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 505424634651 + ... + 505424634676.

It is an arithmetic number, because the mean of its divisors is an integer number (3537972442648).

Almost surely, 213141040501251 is an apocalyptic number.

13141040501251 is a deficient number, since it is larger than the sum of its proper divisors (1010849269341).

13141040501251 is a wasteful number, since it uses less digits than its factorization.

13141040501251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1010849269340.

The product of its (nonzero) digits is 2400, while the sum is 28.

Adding to 13141040501251 its reverse (15210504014131), we get a palindrome (28351544515382).

The spelling of 13141040501251 in words is "thirteen trillion, one hundred forty-one billion, forty million, five hundred one thousand, two hundred fifty-one".

Divisors: 1 13 1010849269327 13141040501251