13141200000 has 384 divisors, whose sum is σ = 44749635840. Its totient is φ = 3415040000.

The previous prime is 13141199999. The next prime is 13141200001. The reversal of 13141200000 is 214131.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (13141199999) and next prime (13141200001).

It is a tau number, because it is divible by the number of its divisors (384).

It is a super-2 number, since 2×13141200000² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is not an unprimeable number, because it can be changed into a prime (13141200001) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 56399884 + ... + 56400116.

It is an arithmetic number, because the mean of its divisors is an integer number (116535510).

Almost surely, 2^13141200000 is an apocalyptic number.

13141200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13141200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22374817920).

13141200000 is an abundant number, since it is smaller than the sum of its proper divisors (31608435840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13141200000 is an frugal number, since it uses more digits than its factorization.

13141200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 322 (or 290 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 13141200000 its reverse (214131), we get a palindrome (13141414131).

The spelling of 13141200000 in words is "thirteen billion, one hundred forty-one million, two hundred thousand".