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13141203423 = 34998778359
BaseRepresentation
bin11000011110100011…
…01101100111011111
31020220211111022010220
430033101231213133
5203403122002143
610011553332423
7643436246265
oct141721554737
936824438126
1013141203423
1156339596a7
122668b67113
131315710a1a
148c9404435
1551da44d83
hex30f46d9df

13141203423 has 8 divisors (see below), whose sum is σ = 17556720000. Its totient is φ = 8743244568.

The previous prime is 13141203409. The next prime is 13141203443. The reversal of 13141203423 is 32430214131.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13141203423 - 24 = 13141203407 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13141203393 and 13141203402.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13141203443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4387683 + ... + 4390676.

It is an arithmetic number, because the mean of its divisors is an integer number (2194590000).

Almost surely, 213141203423 is an apocalyptic number.

13141203423 is a deficient number, since it is larger than the sum of its proper divisors (4415516577).

13141203423 is an equidigital number, since it uses as much as digits as its factorization.

13141203423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8778861.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 13141203423 its reverse (32430214131), we get a palindrome (45571417554).

The spelling of 13141203423 in words is "thirteen billion, one hundred forty-one million, two hundred three thousand, four hundred twenty-three".

Divisors: 1 3 499 1497 8778359 26335077 4380401141 13141203423