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131413112210000 = 245419701986659
BaseRepresentation
bin11101111000010011111111…
…110111110100001001010000
3122020021222012201221100220002
4131320103333313310021100
5114211033023211210000
61143254203400505132
736452166266254145
oct3570237767641120
9566258181840802
10131413112210000
1138965a95a00a05
12128a48a947b1a8
13584328488acaa
1424645dddc23cc
15102d5539228d5
hex7784ffdf4250

131413112210000 has 200 divisors, whose sum is σ = 335387874650400. Its totient is φ = 49727563200000.

The previous prime is 131413112209991. The next prime is 131413112210033. The reversal of 131413112210000 is 12211314131.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 132696671 + ... + 133683329.

It is an arithmetic number, because the mean of its divisors is an integer number (1676939373252).

Almost surely, 2131413112210000 is an apocalyptic number.

131413112210000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131413112210000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (167693937325200).

131413112210000 is an abundant number, since it is smaller than the sum of its proper divisors (203974762440400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131413112210000 is an equidigital number, since it uses as much as digits as its factorization.

131413112210000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 987407 (or 987386 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 131413112210000 its reverse (12211314131), we get a palindrome (131425323524131).

The spelling of 131413112210000 in words is "one hundred thirty-one trillion, four hundred thirteen billion, one hundred twelve million, two hundred ten thousand".