Base | Representation |
---|---|
bin | 11101111000010011111111… |
… | …111010111010011011000111 |
3 | 122020021222012210110121221202 |
4 | 131320103333322322123013 |
5 | 114211033023413202101 |
6 | 1143254203430133115 |
7 | 36452166306206012 |
oct | 3570237772723307 |
9 | 566258183417852 |
10 | 131413113022151 |
11 | 38965a96406104 |
12 | 128a48a97b119b |
13 | 5843284ab385c |
14 | 2464600154379 |
15 | 102d553a3336b |
hex | 7784ffeba6c7 |
131413113022151 has 2 divisors, whose sum is σ = 131413113022152. Its totient is φ = 131413113022150.
The previous prime is 131413113022109. The next prime is 131413113022183. The reversal of 131413113022151 is 151220311314131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131413113022151 - 226 = 131413045913287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131413113022351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65706556511075 + 65706556511076.
It is an arithmetic number, because the mean of its divisors is an integer number (65706556511076).
Almost surely, 2131413113022151 is an apocalyptic number.
131413113022151 is a deficient number, since it is larger than the sum of its proper divisors (1).
131413113022151 is an equidigital number, since it uses as much as digits as its factorization.
131413113022151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 29.
Adding to 131413113022151 its reverse (151220311314131), we get a palindrome (282633424336282).
The spelling of 131413113022151 in words is "one hundred thirty-one trillion, four hundred thirteen billion, one hundred thirteen million, twenty-two thousand, one hundred fifty-one".
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