Base | Representation |
---|---|
bin | 11101111000010100010010… |
… | …110100011110000111010001 |
3 | 122020022000000220002212120211 |
4 | 131320110102310132013101 |
5 | 114211034201101203213 |
6 | 1143254255114204121 |
7 | 36452210206265335 |
oct | 3570242264360721 |
9 | 566260026085524 |
10 | 131413430100433 |
11 | 38966139394778 |
12 | 128a4977a23641 |
13 | 58433056b0c40 |
14 | 24646302d17c5 |
15 | 102d5717b753d |
hex | 778512d1e1d1 |
131413430100433 has 16 divisors (see below), whose sum is σ = 147681481409280. Its totient is φ = 116025724545984.
The previous prime is 131413430100391. The next prime is 131413430100439. The reversal of 131413430100433 is 334001034314131.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 131413430100433 - 225 = 131413396546001 is a prime.
It is a super-2 number, since 2×1314134301004332 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131413430100395 and 131413430100404.
It is not an unprimeable number, because it can be changed into a prime (131413430100439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2053453 + ... + 16341466.
It is an arithmetic number, because the mean of its divisors is an integer number (9230092588080).
Almost surely, 2131413430100433 is an apocalyptic number.
131413430100433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
131413430100433 is a deficient number, since it is larger than the sum of its proper divisors (16268051308847).
131413430100433 is a wasteful number, since it uses less digits than its factorization.
131413430100433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18418848.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 131413430100433 its reverse (334001034314131), we get a palindrome (465414464414564).
The spelling of 131413430100433 in words is "one hundred thirty-one trillion, four hundred thirteen billion, four hundred thirty million, one hundred thousand, four hundred thirty-three".
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