Base | Representation |
---|---|
bin | 1011111100111011010100… |
… | …1110101111110001010101 |
3 | 1201112022002221222220101002 |
4 | 2333032311032233301111 |
5 | 3210301433422001440 |
6 | 43541014545113045 |
7 | 2524300535465054 |
oct | 277166516576125 |
9 | 51468087886332 |
10 | 13141345500245 |
11 | 4207238a39106 |
12 | 1582a6a028785 |
13 | 7442ba2265b1 |
14 | 33608a21a39b |
15 | 17bc83585115 |
hex | bf3b53afc55 |
13141345500245 has 8 divisors (see below), whose sum is σ = 15844352111520. Its totient is φ = 10463251392720.
The previous prime is 13141345500187. The next prime is 13141345500281. The reversal of 13141345500245 is 54200554314131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13141345500245 - 26 = 13141345500181 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13141345500199 and 13141345500208.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6228124775 + ... + 6228126884.
It is an arithmetic number, because the mean of its divisors is an integer number (1980544013940).
Almost surely, 213141345500245 is an apocalyptic number.
It is an amenable number.
13141345500245 is a deficient number, since it is larger than the sum of its proper divisors (2703006611275).
13141345500245 is a wasteful number, since it uses less digits than its factorization.
13141345500245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12456251875.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 13141345500245 its reverse (54200554314131), we get a palindrome (67341899814376).
The spelling of 13141345500245 in words is "thirteen trillion, one hundred forty-one billion, three hundred forty-five million, five hundred thousand, two hundred forty-five".
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