Base | Representation |
---|---|
bin | 1011111100111011100110… |
… | …1111010101001110101111 |
3 | 1201112022022020100100220111 |
4 | 2333032321233111032233 |
5 | 3210302112303314101 |
6 | 43541030250400451 |
7 | 2524302444505456 |
oct | 277167157251657 |
9 | 51468266310814 |
10 | 13141421151151 |
11 | 4207277709817 |
12 | 1582a8b430127 |
13 | 7442ccac3247 |
14 | 3360962adb9d |
15 | 17bc8a02a251 |
hex | bf3b9bd53af |
13141421151151 has 2 divisors, whose sum is σ = 13141421151152. Its totient is φ = 13141421151150.
The previous prime is 13141421151139. The next prime is 13141421151167. The reversal of 13141421151151 is 15115112414131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13141421151151 - 215 = 13141421118383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13141421251151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570710575575 + 6570710575576.
It is an arithmetic number, because the mean of its divisors is an integer number (6570710575576).
Almost surely, 213141421151151 is an apocalyptic number.
13141421151151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13141421151151 is an equidigital number, since it uses as much as digits as its factorization.
13141421151151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2400, while the sum is 31.
Adding to 13141421151151 its reverse (15115112414131), we get a palindrome (28256533565282).
The spelling of 13141421151151 in words is "thirteen trillion, one hundred forty-one billion, four hundred twenty-one million, one hundred fifty-one thousand, one hundred fifty-one".
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