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13341455414131 = 131026265801087
BaseRepresentation
bin1100001000100100110010…
…1101011111001101110011
31202020102121222002210101011
43002021030231133031303
53222041300041223011
644212551403051351
72544613462624525
oct302111455371563
952212558083334
1013341455414131
114284096852229
1215b57b6510b57
1375a12b24a870
14341a30b4da15
151820964bb621
hexc224cb5f373

13341455414131 has 4 divisors (see below), whose sum is σ = 14367721215232. Its totient is φ = 12315189613032.

The previous prime is 13341455414059. The next prime is 13341455414143. The reversal of 13341455414131 is 13141455414331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13341455414131 - 217 = 13341455283059 is a prime.

It is a super-2 number, since 2×133414554141312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13341455414731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 513132900531 + ... + 513132900556.

It is an arithmetic number, because the mean of its divisors is an integer number (3591930303808).

Almost surely, 213341455414131 is an apocalyptic number.

13341455414131 is a deficient number, since it is larger than the sum of its proper divisors (1026265801101).

13341455414131 is a wasteful number, since it uses less digits than its factorization.

13341455414131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1026265801100.

The product of its digits is 172800, while the sum is 40.

The spelling of 13341455414131 in words is "thirteen trillion, three hundred forty-one billion, four hundred fifty-five million, four hundred fourteen thousand, one hundred thirty-one".

Divisors: 1 13 1026265801087 13341455414131