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13142010023 is a prime number
BaseRepresentation
bin11000011110101001…
…10010100010100111
31020220220000021120222
430033110302202213
5203403323310043
610012022514555
7643446146012
oct141724624247
936826007528
1013142010023
11563435a70a
122669295a5b
131315933bbc
148c9574379
1551db53d68
hex30f5328a7

13142010023 has 2 divisors, whose sum is σ = 13142010024. Its totient is φ = 13142010022.

The previous prime is 13142010019. The next prime is 13142010053. The reversal of 13142010023 is 32001024131.

13142010023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13142010023 - 22 = 13142010019 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 13142009983 and 13142010010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13142010053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571005011 + 6571005012.

It is an arithmetic number, because the mean of its divisors is an integer number (6571005012).

Almost surely, 213142010023 is an apocalyptic number.

13142010023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13142010023 is an equidigital number, since it uses as much as digits as its factorization.

13142010023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13142010023 its reverse (32001024131), we get a palindrome (45143034154).

The spelling of 13142010023 in words is "thirteen billion, one hundred forty-two million, ten thousand, twenty-three".