13142011 has 2 divisors, whose sum is σ = 13142012. Its totient is φ = 13142010.

The previous prime is 13142009. The next prime is 13142027. The reversal of 13142011 is 11024131.

It is a weak prime.

It is an emirp because it is prime and its reverse (11024131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13142011 - 2¹ = 13142009 is a prime.

Together with 13142009, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13141982 and 13142000.

It is not a weakly prime, because it can be changed into another prime (13142111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571005 + 6571006.

It is an arithmetic number, because the mean of its divisors is an integer number (6571006).

Almost surely, 2^13142011 is an apocalyptic number.

13142011 is a deficient number, since it is larger than the sum of its proper divisors (1).

13142011 is an equidigital number, since it uses as much as digits as its factorization.

13142011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 13142011 is about 3625.1911673731. The cubic root of 13142011 is about 235.9865632013.

Adding to 13142011 its reverse (11024131), we get a palindrome (24166142).

The spelling of 13142011 in words is "thirteen million, one hundred forty-two thousand, eleven".