Base | Representation |
---|---|
bin | 111101001100101000… |
… | …1011000110101110111 |
3 | 110120012220211200010022 |
4 | 1322121101120311313 |
5 | 4123122121204002 |
6 | 140212421115355 |
7 | 12331502512622 |
oct | 1723121306567 |
9 | 416186750108 |
10 | 131420491127 |
11 | 5080a494142 |
12 | 21578558b5b |
13 | c515279123 |
14 | 6509dd2db9 |
15 | 3642904ba2 |
hex | 1e99458d77 |
131420491127 has 2 divisors, whose sum is σ = 131420491128. Its totient is φ = 131420491126.
The previous prime is 131420491087. The next prime is 131420491129. The reversal of 131420491127 is 721194024131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131420491127 - 226 = 131353382263 is a prime.
Together with 131420491129, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131420491129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65710245563 + 65710245564.
It is an arithmetic number, because the mean of its divisors is an integer number (65710245564).
Almost surely, 2131420491127 is an apocalyptic number.
131420491127 is a deficient number, since it is larger than the sum of its proper divisors (1).
131420491127 is an equidigital number, since it uses as much as digits as its factorization.
131420491127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 35.
The spelling of 131420491127 in words is "one hundred thirty-one billion, four hundred twenty million, four hundred ninety-one thousand, one hundred twenty-seven".
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