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1314214240231 is a prime number
BaseRepresentation
bin10011000111111101010…
…001011101111111100111
311122122012211221200011001
4103013331101131333213
5133013002321141411
62443424112054131
7163643311504114
oct23077521357747
94578184850131
101314214240231
1146739a74a272
12192853834347
1396c11c08189
14478732ad90b
15242bbc76dc1
hex131fd45dfe7

1314214240231 has 2 divisors, whose sum is σ = 1314214240232. Its totient is φ = 1314214240230.

The previous prime is 1314214240211. The next prime is 1314214240243. The reversal of 1314214240231 is 1320424124131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1314214240231 - 27 = 1314214240103 is a prime.

It is a super-2 number, since 2×13142142402312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1314214240231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1314214240211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657107120115 + 657107120116.

It is an arithmetic number, because the mean of its divisors is an integer number (657107120116).

Almost surely, 21314214240231 is an apocalyptic number.

1314214240231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314214240231 is an equidigital number, since it uses as much as digits as its factorization.

1314214240231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1314214240231 its reverse (1320424124131), we get a palindrome (2634638364362).

The spelling of 1314214240231 in words is "one trillion, three hundred fourteen billion, two hundred fourteen million, two hundred forty thousand, two hundred thirty-one".