Base | Representation |
---|---|
bin | 10011000111111101010… |
… | …001011101111111100111 |
3 | 11122122012211221200011001 |
4 | 103013331101131333213 |
5 | 133013002321141411 |
6 | 2443424112054131 |
7 | 163643311504114 |
oct | 23077521357747 |
9 | 4578184850131 |
10 | 1314214240231 |
11 | 46739a74a272 |
12 | 192853834347 |
13 | 96c11c08189 |
14 | 478732ad90b |
15 | 242bbc76dc1 |
hex | 131fd45dfe7 |
1314214240231 has 2 divisors, whose sum is σ = 1314214240232. Its totient is φ = 1314214240230.
The previous prime is 1314214240211. The next prime is 1314214240243. The reversal of 1314214240231 is 1320424124131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1314214240231 - 27 = 1314214240103 is a prime.
It is a super-2 number, since 2×13142142402312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1314214240231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314214240211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657107120115 + 657107120116.
It is an arithmetic number, because the mean of its divisors is an integer number (657107120116).
Almost surely, 21314214240231 is an apocalyptic number.
1314214240231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314214240231 is an equidigital number, since it uses as much as digits as its factorization.
1314214240231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 1314214240231 its reverse (1320424124131), we get a palindrome (2634638364362).
The spelling of 1314214240231 in words is "one trillion, three hundred fourteen billion, two hundred fourteen million, two hundred forty thousand, two hundred thirty-one".
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