Base | Representation |
---|---|
bin | 100111001010101… |
… | …0101010110101101 |
3 | 10101120221001112021 |
4 | 1032111111112231 |
5 | 10142414342331 |
6 | 334224110141 |
7 | 44365434415 |
oct | 11625252655 |
9 | 3346831467 |
10 | 1314215341 |
11 | 61492748a |
12 | 308165351 |
13 | 17c37441a |
14 | c6781645 |
15 | 7a59c211 |
hex | 4e5555ad |
1314215341 has 2 divisors, whose sum is σ = 1314215342. Its totient is φ = 1314215340.
The previous prime is 1314215291. The next prime is 1314215347. The reversal of 1314215341 is 1435124131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1256986116 + 57229225 = 35454^2 + 7565^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314215341 - 211 = 1314213293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314215347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657107670 + 657107671.
It is an arithmetic number, because the mean of its divisors is an integer number (657107671).
Almost surely, 21314215341 is an apocalyptic number.
It is an amenable number.
1314215341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314215341 is an equidigital number, since it uses as much as digits as its factorization.
1314215341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1440, while the sum is 25.
The square root of 1314215341 is about 36252.1080904270. The cubic root of 1314215341 is about 1095.3565531250.
Adding to 1314215341 its reverse (1435124131), we get a palindrome (2749339472).
The spelling of 1314215341 in words is "one billion, three hundred fourteen million, two hundred fifteen thousand, three hundred forty-one".
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