Base | Representation |
---|---|
bin | 10011000111111101101… |
… | …100110110111001101111 |
3 | 11122122020100110110010201 |
4 | 103013331230312321233 |
5 | 133013011140421033 |
6 | 2443424530014331 |
7 | 163643426516602 |
oct | 23077554667157 |
9 | 4578210413121 |
10 | 1314221420143 |
11 | 4673a3803685 |
12 | 1928561173a7 |
13 | 96c13550248 |
14 | 4787421c339 |
15 | 242bc6e447d |
hex | 131fdb36e6f |
1314221420143 has 2 divisors, whose sum is σ = 1314221420144. Its totient is φ = 1314221420142.
The previous prime is 1314221420119. The next prime is 1314221420173. The reversal of 1314221420143 is 3410241224131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1314221420143 - 221 = 1314219322991 is a prime.
It is a super-2 number, since 2×13142214201432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314221420173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657110710071 + 657110710072.
It is an arithmetic number, because the mean of its divisors is an integer number (657110710072).
Almost surely, 21314221420143 is an apocalyptic number.
1314221420143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314221420143 is an equidigital number, since it uses as much as digits as its factorization.
1314221420143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 1314221420143 its reverse (3410241224131), we get a palindrome (4724462644274).
The spelling of 1314221420143 in words is "one trillion, three hundred fourteen billion, two hundred twenty-one million, four hundred twenty thousand, one hundred forty-three".
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