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1314221420143 is a prime number
BaseRepresentation
bin10011000111111101101…
…100110110111001101111
311122122020100110110010201
4103013331230312321233
5133013011140421033
62443424530014331
7163643426516602
oct23077554667157
94578210413121
101314221420143
114673a3803685
121928561173a7
1396c13550248
144787421c339
15242bc6e447d
hex131fdb36e6f

1314221420143 has 2 divisors, whose sum is σ = 1314221420144. Its totient is φ = 1314221420142.

The previous prime is 1314221420119. The next prime is 1314221420173. The reversal of 1314221420143 is 3410241224131.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1314221420143 - 221 = 1314219322991 is a prime.

It is a super-2 number, since 2×13142214201432 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1314221420173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657110710071 + 657110710072.

It is an arithmetic number, because the mean of its divisors is an integer number (657110710072).

Almost surely, 21314221420143 is an apocalyptic number.

1314221420143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314221420143 is an equidigital number, since it uses as much as digits as its factorization.

1314221420143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1314221420143 its reverse (3410241224131), we get a palindrome (4724462644274).

The spelling of 1314221420143 in words is "one trillion, three hundred fourteen billion, two hundred twenty-one million, four hundred twenty thousand, one hundred forty-three".