Base | Representation |
---|---|
bin | 1011111100111110101001… |
… | …0001011111000001101100 |
3 | 1201112101101222112000210122 |
4 | 2333033222101133001230 |
5 | 3210310244231114130 |
6 | 43541243135024112 |
7 | 2524331562551525 |
oct | 277175221370154 |
9 | 51471358460718 |
10 | 13142235410540 |
11 | 42076552a9965 |
12 | 158307806b038 |
13 | 7443cc6c9632 |
14 | 3361324ab84c |
15 | 17bcd676c2e5 |
hex | bf3ea45f06c |
13142235410540 has 96 divisors (see below), whose sum is σ = 28411077408000. Its totient is φ = 5104388689920.
The previous prime is 13142235410537. The next prime is 13142235410581. The reversal of 13142235410540 is 4501453224131.
It is a self number, because there is not a number n which added to its sum of digits gives 13142235410540.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1090726436 + ... + 1090738484.
It is an arithmetic number, because the mean of its divisors is an integer number (295948723000).
Almost surely, 213142235410540 is an apocalyptic number.
13142235410540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13142235410540 is an abundant number, since it is smaller than the sum of its proper divisors (15268841997460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13142235410540 is a wasteful number, since it uses less digits than its factorization.
13142235410540 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23515 (or 23513 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 13142235410540 its reverse (4501453224131), we get a palindrome (17643688634671).
The spelling of 13142235410540 in words is "thirteen trillion, one hundred forty-two billion, two hundred thirty-five million, four hundred ten thousand, five hundred forty".
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