Base | Representation |
---|---|
bin | 1011111100111110111011… |
… | …0000000110001011001111 |
3 | 1201112101121012220012122022 |
4 | 2333033232300012023033 |
5 | 3210310422444402304 |
6 | 43541254421240355 |
7 | 2524333464305663 |
oct | 277175660061317 |
9 | 51471535805568 |
10 | 13142310544079 |
11 | 42076937568a2 |
12 | 15830992630bb |
13 | 744412144952 |
14 | 33613c4688a3 |
15 | 17bcdd15debe |
hex | bf3eec062cf |
13142310544079 has 2 divisors, whose sum is σ = 13142310544080. Its totient is φ = 13142310544078.
The previous prime is 13142310544067. The next prime is 13142310544081. The reversal of 13142310544079 is 97044501324131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13142310544079 - 240 = 12042798916303 is a prime.
It is a super-2 number, since 2×131423105440792 (a number of 27 digits) contains 22 as substring.
Together with 13142310544081, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13142310549079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571155272039 + 6571155272040.
It is an arithmetic number, because the mean of its divisors is an integer number (6571155272040).
Almost surely, 213142310544079 is an apocalyptic number.
13142310544079 is a deficient number, since it is larger than the sum of its proper divisors (1).
13142310544079 is an equidigital number, since it uses as much as digits as its factorization.
13142310544079 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 44.
The spelling of 13142310544079 in words is "thirteen trillion, one hundred forty-two billion, three hundred ten million, five hundred forty-four thousand, seventy-nine".
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