Base | Representation |
---|---|
bin | 1011111100111110111011… |
… | …0000000110001110101111 |
3 | 1201112101121012220012221121 |
4 | 2333033232300012032233 |
5 | 3210310422444404203 |
6 | 43541254421241411 |
7 | 2524333464306433 |
oct | 277175660061657 |
9 | 51471535805847 |
10 | 13142310544303 |
11 | 4207693756a86 |
12 | 1583099263267 |
13 | 744412144a95 |
14 | 33613c4689c3 |
15 | 17bcdd15e0bd |
hex | bf3eec063af |
13142310544303 has 2 divisors, whose sum is σ = 13142310544304. Its totient is φ = 13142310544302.
The previous prime is 13142310544289. The next prime is 13142310544327. The reversal of 13142310544303 is 30344501324131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13142310544303 is a prime.
It is a super-2 number, since 2×131423105443032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13142310544903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571155272151 + 6571155272152.
It is an arithmetic number, because the mean of its divisors is an integer number (6571155272152).
Almost surely, 213142310544303 is an apocalyptic number.
13142310544303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13142310544303 is an equidigital number, since it uses as much as digits as its factorization.
13142310544303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 13142310544303 its reverse (30344501324131), we get a palindrome (43486811868434).
The spelling of 13142310544303 in words is "thirteen trillion, one hundred forty-two billion, three hundred ten million, five hundred forty-four thousand, three hundred three".
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