Base | Representation |
---|---|
bin | 1011111100111110111011… |
… | …0000000110001111000111 |
3 | 1201112101121012220012222111 |
4 | 2333033232300012033013 |
5 | 3210310422444404302 |
6 | 43541254421241451 |
7 | 2524333464306466 |
oct | 277175660061707 |
9 | 51471535805874 |
10 | 13142310544327 |
11 | 4207693756aa8 |
12 | 1583099263287 |
13 | 744412144ab3 |
14 | 33613c4689dd |
15 | 17bcdd15e0d7 |
hex | bf3eec063c7 |
13142310544327 has 2 divisors, whose sum is σ = 13142310544328. Its totient is φ = 13142310544326.
The previous prime is 13142310544303. The next prime is 13142310544339. The reversal of 13142310544327 is 72344501324131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13142310544327 - 27 = 13142310544199 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13142310544327.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13142310542327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571155272163 + 6571155272164.
It is an arithmetic number, because the mean of its divisors is an integer number (6571155272164).
Almost surely, 213142310544327 is an apocalyptic number.
13142310544327 is a deficient number, since it is larger than the sum of its proper divisors (1).
13142310544327 is an equidigital number, since it uses as much as digits as its factorization.
13142310544327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 40.
Adding to 13142310544327 its reverse (72344501324131), we get a palindrome (85486811868458).
The spelling of 13142310544327 in words is "thirteen trillion, one hundred forty-two billion, three hundred ten million, five hundred forty-four thousand, three hundred twenty-seven".
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