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13142310544321 = 71877472934903
BaseRepresentation
bin1011111100111110111011…
…0000000110001111000001
31201112101121012220012222021
42333033232300012033001
53210310422444404241
643541254421241441
72524333464306460
oct277175660061701
951471535805867
1013142310544321
114207693756aa2
121583099263281
13744412144aaa
1433613c4689d7
1517bcdd15e0d1
hexbf3eec063c1

13142310544321 has 4 divisors (see below), whose sum is σ = 15019783479232. Its totient is φ = 11264837609412.

The previous prime is 13142310544303. The next prime is 13142310544327. The reversal of 13142310544321 is 12344501324131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13142310544321 - 25 = 13142310544289 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13142310544327) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 938736467445 + ... + 938736467458.

It is an arithmetic number, because the mean of its divisors is an integer number (3754945869808).

Almost surely, 213142310544321 is an apocalyptic number.

It is an amenable number.

13142310544321 is a deficient number, since it is larger than the sum of its proper divisors (1877472934911).

13142310544321 is an equidigital number, since it uses as much as digits as its factorization.

13142310544321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1877472934910.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 13142310544321 its reverse (12344501324131), we get a palindrome (25486811868452).

The spelling of 13142310544321 in words is "thirteen trillion, one hundred forty-two billion, three hundred ten million, five hundred forty-four thousand, three hundred twenty-one".

Divisors: 1 7 1877472934903 13142310544321