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131423131011013 is a prime number
BaseRepresentation
bin11101111000011101010101…
…000010100000011111000101
3122020022221001222002012011021
4131320131111002200133011
5114211214033014323023
61143302541454311141
736453002462542432
oct3570352502403705
9566287058065137
10131423131011013
113896a267297446
12128a68247b84b1
1358441c042bc0a
142464cb083ab89
15102d93d29635d
hex7787550a07c5

131423131011013 has 2 divisors, whose sum is σ = 131423131011014. Its totient is φ = 131423131011012.

The previous prime is 131423131010999. The next prime is 131423131011019. The reversal of 131423131011013 is 310110131324131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90948685036804 + 40474445974209 = 9536702^2 + 6361953^2 .

It is a cyclic number.

It is not a de Polignac number, because 131423131011013 - 25 = 131423131010981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131423131011019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65711565505506 + 65711565505507.

It is an arithmetic number, because the mean of its divisors is an integer number (65711565505507).

Almost surely, 2131423131011013 is an apocalyptic number.

It is an amenable number.

131423131011013 is a deficient number, since it is larger than the sum of its proper divisors (1).

131423131011013 is an equidigital number, since it uses as much as digits as its factorization.

131423131011013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 131423131011013 its reverse (310110131324131), we get a palindrome (441533262335144).

The spelling of 131423131011013 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, one hundred thirty-one million, eleven thousand, thirteen".