131423143331233 has 4 divisors (see below), whose sum is σ = 141532615895188. Its totient is φ = 121313670767280.

The previous prime is 131423143331201. The next prime is 131423143331237. The reversal of 131423143331233 is 332133341324131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 27212999025664 + 104210144305569 = 5216608^2 + 10208337^2 .

It is a cyclic number.

It is not a de Polignac number, because 131423143331233 - 2⁵ = 131423143331201 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131423143331192 and 131423143331201.

It is not an unprimeable number, because it can be changed into a prime (131423143331237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5054736281958 + ... + 5054736281983.

It is an arithmetic number, because the mean of its divisors is an integer number (35383153973797).

Almost surely, 2^{131423143331233} is an apocalyptic number.

131423143331233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

131423143331233 is a deficient number, since it is larger than the sum of its proper divisors (10109472563955).

131423143331233 is a wasteful number, since it uses less digits than its factorization.

131423143331233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10109472563954.

The product of its digits is 139968, while the sum is 37.

Adding to 131423143331233 its reverse (332133341324131), we get a palindrome (463556484655364).

The spelling of 131423143331233 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, one hundred forty-three million, three hundred thirty-one thousand, two hundred thirty-three".