Base | Representation |
---|---|
bin | 10011000111111110011… |
… | …011000100011110001111 |
3 | 11122122021012020220201002 |
4 | 103013332123010132033 |
5 | 133013022241044401 |
6 | 2443430041410515 |
7 | 163643634503153 |
oct | 23077633043617 |
9 | 4578235226632 |
10 | 1314233534351 |
11 | 4673aa628221 |
12 | 19285a199a3b |
13 | 96c15c0220a |
14 | 47875a93063 |
15 | 242bd7d8a6b |
hex | 131fe6c478f |
1314233534351 has 2 divisors, whose sum is σ = 1314233534352. Its totient is φ = 1314233534350.
The previous prime is 1314233534347. The next prime is 1314233534389. The reversal of 1314233534351 is 1534353324131.
It is an a-pointer prime, because the next prime (1314233534389) can be obtained adding 1314233534351 to its sum of digits (38).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1314233534351 - 22 = 1314233534347 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1314233534321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657116767175 + 657116767176.
It is an arithmetic number, because the mean of its divisors is an integer number (657116767176).
Almost surely, 21314233534351 is an apocalyptic number.
1314233534351 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314233534351 is an equidigital number, since it uses as much as digits as its factorization.
1314233534351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 194400, while the sum is 38.
Adding to 1314233534351 its reverse (1534353324131), we get a palindrome (2848586858482).
The spelling of 1314233534351 in words is "one trillion, three hundred fourteen billion, two hundred thirty-three million, five hundred thirty-four thousand, three hundred fifty-one".
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