131424140143001 has 2 divisors, whose sum is σ = 131424140143002. Its totient is φ = 131424140143000.

The previous prime is 131424140142973. The next prime is 131424140143003. The reversal of 131424140143001 is 100341041424131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127992476517376 + 3431663625625 = 11313376^2 + 1852475^2 .

It is an emirp because it is prime and its reverse (100341041424131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131424140143001 is a prime.

It is a super-2 number, since 2×131424140143001² (a number of 29 digits) contains 22 as substring.

Together with 131424140143003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131424140143003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65712070071500 + 65712070071501.

It is an arithmetic number, because the mean of its divisors is an integer number (65712070071501).

Almost surely, 2^{131424140143001} is an apocalyptic number.

It is an amenable number.

131424140143001 is a deficient number, since it is larger than the sum of its proper divisors (1).

131424140143001 is an equidigital number, since it uses as much as digits as its factorization.

131424140143001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 131424140143001 its reverse (100341041424131), we get a palindrome (231765181567132).

The spelling of 131424140143001 in words is "one hundred thirty-one trillion, four hundred twenty-four billion, one hundred forty million, one hundred forty-three thousand, one".