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13143054333 = 34381018111
BaseRepresentation
bin11000011110110001…
…10001011111111101
31020220221222100010010
430033120301133331
5203404110214313
610012101133433
7643461055443
oct141730613775
936827870103
1013143054333
115634a03282
1226696ba279
131315c0b336
148c9766b93
1551dcad4c3
hex30f6317fd

13143054333 has 4 divisors (see below), whose sum is σ = 17524072448. Its totient is φ = 8762036220.

The previous prime is 13143054317. The next prime is 13143054343. The reversal of 13143054333 is 33345034131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13143054333 - 24 = 13143054317 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13143054333.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13143054343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2190509053 + ... + 2190509058.

It is an arithmetic number, because the mean of its divisors is an integer number (4381018112).

Almost surely, 213143054333 is an apocalyptic number.

It is an amenable number.

13143054333 is a deficient number, since it is larger than the sum of its proper divisors (4381018115).

13143054333 is an equidigital number, since it uses as much as digits as its factorization.

13143054333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4381018114.

The product of its (nonzero) digits is 19440, while the sum is 30.

Adding to 13143054333 its reverse (33345034131), we get a palindrome (46488088464).

The spelling of 13143054333 in words is "thirteen billion, one hundred forty-three million, fifty-four thousand, three hundred thirty-three".

Divisors: 1 3 4381018111 13143054333