Base | Representation |
---|---|
bin | 11101111000100100110000… |
… | …001001011111100111001011 |
3 | 122020100200122110221101220221 |
4 | 131320210300021133213023 |
5 | 114211331344104120133 |
6 | 1143310340440530511 |
7 | 36453404142156010 |
oct | 3570446011374713 |
9 | 566320573841827 |
10 | 131431102020043 |
11 | 38972687763511 |
12 | 128a828a180a37 |
13 | 5844b909613c7 |
14 | 2465429319707 |
15 | 102dc57e66a2d |
hex | 77893025f9cb |
131431102020043 has 4 divisors (see below), whose sum is σ = 150206973737200. Its totient is φ = 112655230302888.
The previous prime is 131431102020017. The next prime is 131431102020047. The reversal of 131431102020043 is 340020201134131.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-131431102020043 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131431102020047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9387935858568 + ... + 9387935858581.
It is an arithmetic number, because the mean of its divisors is an integer number (37551743434300).
Almost surely, 2131431102020043 is an apocalyptic number.
131431102020043 is a deficient number, since it is larger than the sum of its proper divisors (18775871717157).
131431102020043 is an equidigital number, since it uses as much as digits as its factorization.
131431102020043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18775871717156.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 131431102020043 its reverse (340020201134131), we get a palindrome (471451303154174).
The spelling of 131431102020043 in words is "one hundred thirty-one trillion, four hundred thirty-one billion, one hundred two million, twenty thousand, forty-three".
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