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131431102020043 = 718775871717149
BaseRepresentation
bin11101111000100100110000…
…001001011111100111001011
3122020100200122110221101220221
4131320210300021133213023
5114211331344104120133
61143310340440530511
736453404142156010
oct3570446011374713
9566320573841827
10131431102020043
1138972687763511
12128a828a180a37
135844b909613c7
142465429319707
15102dc57e66a2d
hex77893025f9cb

131431102020043 has 4 divisors (see below), whose sum is σ = 150206973737200. Its totient is φ = 112655230302888.

The previous prime is 131431102020017. The next prime is 131431102020047. The reversal of 131431102020043 is 340020201134131.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-131431102020043 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131431102020047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9387935858568 + ... + 9387935858581.

It is an arithmetic number, because the mean of its divisors is an integer number (37551743434300).

Almost surely, 2131431102020043 is an apocalyptic number.

131431102020043 is a deficient number, since it is larger than the sum of its proper divisors (18775871717157).

131431102020043 is an equidigital number, since it uses as much as digits as its factorization.

131431102020043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18775871717156.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 131431102020043 its reverse (340020201134131), we get a palindrome (471451303154174).

The spelling of 131431102020043 in words is "one hundred thirty-one trillion, four hundred thirty-one billion, one hundred two million, twenty thousand, forty-three".

Divisors: 1 7 18775871717149 131431102020043