131431102020044 has 6 divisors (see below), whose sum is σ = 230004428535084. Its totient is φ = 65715551010020.

The previous prime is 131431102020017. The next prime is 131431102020047. The reversal of 131431102020044 is 440020201134131.

It is a super-4 number, since 4×131431102020044⁴ (a number of 58 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131431102019995 and 131431102020022.

It is not an unprimeable number, because it can be changed into a prime (131431102020047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16428887752502 + ... + 16428887752509.

It is an arithmetic number, because the mean of its divisors is an integer number (38334071422514).

Almost surely, 2^{131431102020044} is an apocalyptic number.

It is an amenable number.

131431102020044 is a deficient number, since it is larger than the sum of its proper divisors (98573326515040).

131431102020044 is a wasteful number, since it uses less digits than its factorization.

131431102020044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32857775505015 (or 32857775505013 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 131431102020044 its reverse (440020201134131), we get a palindrome (571451303154175).

The spelling of 131431102020044 in words is "one hundred thirty-one trillion, four hundred thirty-one billion, one hundred two million, twenty thousand, forty-four".