Search a number
-
+
1314311303103 = 3835278358647
BaseRepresentation
bin10011001000000011000…
…011101110111110111111
311122122110121120222101020
4103020003003232332333
5133013202143144403
62443441500315223
7163645600514211
oct23100303567677
94578417528336
101314311303103
1146743a515017
12192880242b13
1396c29060b26
14478821385b1
15242c554b453
hex132030eefbf

1314311303103 has 8 divisors (see below), whose sum is σ = 1773528505728. Its totient is φ = 865650817944.

The previous prime is 1314311302991. The next prime is 1314311303119. The reversal of 1314311303103 is 3013031134131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1314311303103 - 222 = 1314307108799 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314311303143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2639179075 + ... + 2639179572.

It is an arithmetic number, because the mean of its divisors is an integer number (221691063216).

Almost surely, 21314311303103 is an apocalyptic number.

1314311303103 is a deficient number, since it is larger than the sum of its proper divisors (459217202625).

1314311303103 is an equidigital number, since it uses as much as digits as its factorization.

1314311303103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5278358733.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 1314311303103 its reverse (3013031134131), we get a palindrome (4327342437234).

The spelling of 1314311303103 in words is "one trillion, three hundred fourteen billion, three hundred eleven million, three hundred three thousand, one hundred three".

Divisors: 1 3 83 249 5278358647 15835075941 438103767701 1314311303103